What is sec(7+(2x)/(x^3)) ?

The solution to sec(7+(2x)/(x^3)) is 1/(cos(7+\frac{2){x^2})}

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simplify sec(7+(2x)/(x^3))

simplify

sec (7 + \frac{2 x}{x ^{3}})

\frac{1}{cos ( 7 + \frac{2}{x ^{2}} )}

Solution steps

sec (7 + \frac{2 x}{x ^{3}})

Rewrite using trig identities

= \frac{1}{cos ( 7 ) cos ( \frac{2}{x ^{2}} ) - sin ( 7 ) sin ( \frac{2}{x ^{2}} )}

Use the Angle Sum identity:

cos (s) cos (t) - sin (s) sin (t) = cos (s + t)

= \frac{1}{cos ( 7 + \frac{2}{x ^{2}} )}

csc (θ + 9 π)

cos (arcsin (6 x^{5}))

sin (x) sin (- 4 x)

3 sin (4 \cdot x + 5 π)

cos (arccos (\frac{- x}{3}))

What is sec(7+(2x)/(x^3)) ?
The solution to sec(7+(2x)/(x^3)) is 1/(cos(7+\frac{2){x^2})}