What are the solutions to the equation (x+3)^2=23 ?

The solutions to the equation (x+3)^2=23 are x=sqrt(23)-3,x=-sqrt(23)-3

Find the zeros of (x+3)^2=23

The zeros of (x+3)^2=23 are x=sqrt(23)-3,x=-sqrt(23)-3

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(x + 3)^{2} = 23

x = 23 - 3, x = - 23 - 3

Decimal Notation

x = 1.79583 \dots, x = - 7.79583 \dots

Solution steps

(x + 3)^{2} = 23

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 23 : x = 23 - 3

Solve

x + 3 = - 23 : x = - 23 - 3

The solutions to the quadratic equation are:

x = 23 - 3, x = - 23 - 3

\frac{- 5}{3 ^{2}}

\frac{2}{5} x + \frac{2}{5} = \frac{5}{6}

27 x^{3} + 64 x^{3}

3^{x} \geq 2

(1 + 2 i) \cdot (3 - 4 i)

What are the solutions to the equation (x+3)^2=23 ?
The solutions to the equation (x+3)^2=23 are x=sqrt(23)-3,x=-sqrt(23)-3
Find the zeros of (x+3)^2=23
The zeros of (x+3)^2=23 are x=sqrt(23)-3,x=-sqrt(23)-3