What is (sin(-2pi+x))/(cos(3pi-x)) ?

The solution to (sin(-2pi+x))/(cos(3pi-x)) is -tan(x)

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simplify (sin(-2pi+x))/(cos(3pi-x))

simplify

\frac{sin ( - 2 π + x )}{cos ( 3 π - x )}

- tan (x)

Solution steps

\frac{sin ( - 2 π + x )}{cos ( 3 π - x )}

Rewrite using trig identities

= \frac{sin ( x )}{cos ( 3 π - x )}

Rewrite using trig identities

= \frac{sin ( x )}{- cos ( x )}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{sin ( x )}{cos ( x )}

Rewrite using trig identities

= - tan (x)

2 sec^{2} (\frac{π}{2} - θ)

sin (- 7 x)

\frac{csc ( - sin ( x ) )}{cot ( x )}

cos (- θ) tan (- θ) csc (- θ)

cos (6 0^{\circ} - θ)

What is (sin(-2pi+x))/(cos(3pi-x)) ?
The solution to (sin(-2pi+x))/(cos(3pi-x)) is -tan(x)