What is 4sin(3i^2n^4-4+5) ?

The solution to 4sin(3i^2n^4-4+5) is 4sin(3i^2n^4+1)

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simplify 4sin(3i^2n^4-4+5)

simplify

4 sin (3 i^{2} n^{4} - 4 + 5)

4 sin (3 i^{2} n^{4} + 1)

Solution steps

4 sin (3 i^{2} n^{4} - 4 + 5)

Rewrite using trig identities

= 4 sin (3 i^{2} n^{4} + 1)

f (x) = 8.06 sin (x - 29.7 4^{\circ})

5 sin (- t)

sin (\frac{- 5 x}{4})

3 - 3 sin^{2} (x)

2 cos (\cdot (- s) in x)

What is 4sin(3i^2n^4-4+5) ?
The solution to 4sin(3i^2n^4-4+5) is 4sin(3i^2n^4+1)