What is 2/(n^2pi)cos(n-pi) ?

The solution to 2/(n^2pi)cos(n-pi) is -(2cos(n))/(pin^2)

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simplify 2/(n^2pi)cos(n-pi)

simplify

\frac{2}{n ^{2} π} cos (n - π)

- \frac{2 cos ( n )}{π n ^{2}}

Solution steps

\frac{2}{n ^{2} π} cos (n - π)

Rewrite using trig identities

= \frac{2}{n ^{2} π} (- cos (n))

Simplify

\frac{2}{n ^{2} π} (- cos (n)) : - \frac{2 cos ( n )}{π n ^{2}}

= - \frac{2 cos ( n )}{π n ^{2}}

cos (arctan (\frac{d}{a}))

tan (\frac{π}{4} - \frac{x}{2})

sin (108 0^{\circ} - x)

cos (arctan (x + 0.5))

csc^{2} (- csc^{2} (x))

What is 2/(n^2pi)cos(n-pi) ?
The solution to 2/(n^2pi)cos(n-pi) is -(2cos(n))/(pin^2)