What are the solutions to the equation 12x^2+20x-64=0 ?

The solutions to the equation 12x^2+20x-64=0 are x=(-5+sqrt(217))/6 ,x=-(5+sqrt(217))/6

Find the zeros of 12x^2+20x-64=0

The zeros of 12x^2+20x-64=0 are x=(-5+sqrt(217))/6 ,x=-(5+sqrt(217))/6

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12 x^{2} + 20 x - 64 = 0

x = \frac{- 5 + 217}{6}, x = - \frac{5 + 217}{6}

Solution steps

12 x^{2} + 20 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 12 ( - 64 )}{2 \cdot 12}

2 0^{2} - 4 \cdot 12 (- 64) = 4217

x_{1, 2} = \frac{- 20 \pm 4 217}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 20 + 4 217}{2 \cdot 12}, x_{2} = \frac{- 20 - 4 217}{2 \cdot 12}

x = \frac{- 20 + 4 217}{2 \cdot 12} : \frac{- 5 + 217}{6}

x = \frac{- 20 - 4 217}{2 \cdot 12} : - \frac{5 + 217}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 217}{6}, x = - \frac{5 + 217}{6}

13 + 2 k = 3 k + 4 (k - 3)

4 x^{2} + 6 x + 2 = 0

3 b (b - 4) + 6 (b - 8)

3 a^{2} + 11 a - 20

\frac{1 + 2 i}{i}

What are the solutions to the equation 12x^2+20x-64=0 ?
The solutions to the equation 12x^2+20x-64=0 are x=(-5+sqrt(217))/6 ,x=-(5+sqrt(217))/6
Find the zeros of 12x^2+20x-64=0
The zeros of 12x^2+20x-64=0 are x=(-5+sqrt(217))/6 ,x=-(5+sqrt(217))/6