What is 1-sin(θ)cos(90-θ) ?

The solution to 1-sin(θ)cos(90-θ) is cos^2(θ)

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simplify 1-sin(θ)cos(90-θ)

simplify

1 - sin (θ) cos (9 0^{\circ} - θ)

cos^{2} (θ)

Solution steps

1 - sin (θ) cos (9 0^{\circ} - θ)

Rewrite using trig identities

= 1 - sin (θ) sin (θ)

sin (θ) sin (θ) = sin^{2} (θ)

= 1 - sin^{2} (θ)

Rewrite using trig identities

= cos^{2} (θ)

\frac{cos ( x )}{sin ( e )}

sin (b - 0.361)

cos (nπ - 1)

- \frac{3}{2} cos (6 x - π) + 2

sin (arccos (6 - x))