What is tan(pi-β)+tan(pi+β) ?

The solution to tan(pi-β)+tan(pi+β) is 0

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simplify tan(pi-β)+tan(pi+β)

simplify

tan (π - β) + tan (π + β)

0

Solution steps

tan (π - β) + tan (π + β)

Rewrite using trig identities

= tan (π - β) + \frac{sin ( β )}{cos ( β )}

Rewrite using trig identities

= - \frac{sin ( β )}{cos ( β )} + \frac{sin ( β )}{cos ( β )}

Add similar elements:

- \frac{sin ( β )}{cos ( β )} + \frac{sin ( β )}{cos ( β )} = 0

= 0

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