What is sin(θ)sin(pi/2-θ) ?

The solution to sin(θ)sin(pi/2-θ) is sin(θ)cos(θ)

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simplify sin(θ)sin(pi/2-θ)

simplify

sin (θ) sin (\frac{π}{2} - θ)

sin (θ) cos (θ)

Solution steps

sin (θ) sin (\frac{π}{2} - θ)

Rewrite using trig identities

= sin (θ) cos (θ)

25 + (5 tan (x))^{2}

cos (\frac{cos ( θ )}{sin ( θ )})

sin (9 0^{\circ} - \frac{a}{2})

cos (72 0^{\circ} - x)

cos (9 0^{\circ} - θ) + sin (θ)