What is 7cos((n+2)pi)-7cos(npi) ?

The solution to 7cos((n+2)pi)-7cos(npi) is 7cos(pi(2+n))-7(-1)^n

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simplify 7cos((n+2)pi)-7cos(npi)

simplify

7 cos ((n + 2) π) - 7 cos (nπ)

7 cos (π (2 + n)) - 7 (- 1)^{n}

Solution steps

7 cos ((n + 2) π) - 7 cos (nπ)

Use the basic trigonometric identity:

cos (nπ) = (- 1)^{n}

= 7 cos (π (2 + n)) - 7 (- 1)^{n}

cos (- 5 x)

sin (cot (- 1 (x)))

cos (nπ (- 1))

cos (kπ) - cos (- kπ)

cos (x - π) + sin (- \frac{π}{2} - x)

What is 7cos((n+2)pi)-7cos(npi) ?
The solution to 7cos((n+2)pi)-7cos(npi) is 7cos(pi(2+n))-7(-1)^n