What are the solutions to the equation 0=(x+2)^2-3 ?

The solutions to the equation 0=(x+2)^2-3 are x=sqrt(3)-2,x=-sqrt(3)-2

Find the zeros of 0=(x+2)^2-3

The zeros of 0=(x+2)^2-3 are x=sqrt(3)-2,x=-sqrt(3)-2

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0 = (x + 2)^{2} - 3

x = 3 - 2, x = - 3 - 2

Solution steps

0 = (x + 2)^{2} - 3

Switch sides

(x + 2)^{2} - 3 = 0

Move

3

to the right side

(x + 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 3 : x = 3 - 2

Solve

x + 2 = - 3 : x = - 3 - 2

The solutions to the quadratic equation are:

x = 3 - 2, x = - 3 - 2

9 x + 15 = 3 x + 15

16 x^{2} - 8 x + 6

1 2^{\frac{3}{2}}

- (- 2 x + 1) = 9 - 14 x

(x^{\frac{1}{3}})^{\frac{1}{2}}

What are the solutions to the equation 0=(x+2)^2-3 ?
The solutions to the equation 0=(x+2)^2-3 are x=sqrt(3)-2,x=-sqrt(3)-2
Find the zeros of 0=(x+2)^2-3
The zeros of 0=(x+2)^2-3 are x=sqrt(3)-2,x=-sqrt(3)-2