What is sqrt(36-(6(sin(θ)))^2) ?

The solution to sqrt(36-(6(sin(θ)))^2) is 6sqrt(cos^2(θ))

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simplify sqrt(36-(6(sin(θ)))^2)

simplify

36 - (6 (sin (θ)))^{2}

6 cos^{2} (θ)

Solution steps

36 - (6 (sin (θ)))^{2}

Remove parentheses:

(a) = a

= 36 - (6 sin (θ))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 36 - 6^{2} sin^{2} (θ)

Factor

36 - 6^{2} sin^{2} (θ) : 36 (1 - sin^{2} (θ))

= 36 (1 - sin^{2} (θ))

Apply radical rule:

assuming

a \geq 0, b \geq 0

= 36 - sin^{2} (θ) + 1

36 = 6

= 6 - sin^{2} (θ) + 1

Rewrite using trig identities

= 6 cos^{2} (θ)

tan (- π + x)

cos (arctan (3 w))

sin (- 1 (2 x - 1))

cos (π - θ) - cos (θ)

cos (x + 20000 π)

What is sqrt(36-(6(sin(θ)))^2) ?
The solution to sqrt(36-(6(sin(θ)))^2) is 6sqrt(cos^2(θ))