What are the solutions to the equation -9p^2+100=0 ?

The solutions to the equation -9p^2+100=0 are p= 10/3 ,p=-10/3

Find the zeros of -9p^2+100=0

The zeros of -9p^2+100=0 are p= 10/3 ,p=-10/3

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- 9 p^{2} + 100 = 0

p = \frac{10}{3}, p = - \frac{10}{3}

Solution steps

- 9 p^{2} + 100 = 0

Move

100

to the right side

- 9 p^{2} = - 100

Divide both sides by

- 9

p^{2} = \frac{100}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = \frac{100}{9}, p = - \frac{100}{9}

\frac{100}{9} = \frac{10}{3}

- \frac{100}{9} = - \frac{10}{3}

p = \frac{10}{3}, p = - \frac{10}{3}

∣ 3 x - 4 ∣ + 5 = 8

4 x^{2} - 2 x^{3} - 2 x

9 x^{2} - 6 x \geq - 1

- 2 (\frac{3}{2})^{1}

\frac{1}{2} x - 4 \leq \frac{1}{3} x + 5

What are the solutions to the equation -9p^2+100=0 ?
The solutions to the equation -9p^2+100=0 are p= 10/3 ,p=-10/3
Find the zeros of -9p^2+100=0
The zeros of -9p^2+100=0 are p= 10/3 ,p=-10/3