What is sin(arccot(2x-4)) ?

The solution to sin(arccot(2x-4)) is (sqrt(4x^2-16x+17))/(4x^2-16x+17)

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simplify sin(arccot(2x-4))

simplify

sin (arccot (2 x - 4))

\frac{4 x ^{2} - 16 x + 17}{4 x ^{2} - 16 x + 17}

Solution steps

sin (arccot (2 x - 4))

Use the following identity:

sin (arccot (x)) = \frac{1 + x ^{2}}{1 + x ^{2}}

= \frac{1 + ( 2 x - 4 ) ^{2}}{1 + ( 2 x - 4 ) ^{2}}

Simplify

= \frac{4 x ^{2} - 16 x + 17}{4 x ^{2} - 16 x + 17}

2^{2} + (2 tan (t))^{2}

cos (12 0^{\circ} - t)

sin (\frac{2}{cos ( 7 x )})

tan (θ - 36 0^{\circ})

y e^{2} cos (6 \cdot (- 3))

What is sin(arccot(2x-4)) ?
The solution to sin(arccot(2x-4)) is (sqrt(4x^2-16x+17))/(4x^2-16x+17)