What is (1-sin^2(x))/(dx) ?

The solution to (1-sin^2(x))/(dx) is (cos^2(x))/(dx)

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simplify (1-sin^2(x))/(dx)

simplify

\frac{1 - sin ^{2} ( x )}{d x}

\frac{cos ^{2} ( x )}{d x}

Solution steps

\frac{1 - sin ^{2} ( x )}{d x}

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - sin^{2} (x) = cos^{2} (x)

= \frac{cos ^{2} ( x )}{d x}

\frac{1}{sec ( v )} d v

10 sin (x + 6 0^{\circ})

2 cos^{x} (+ cos (x) - 1 (0.2 π))

- cos (\frac{π}{4} + t)

sin (arccos (X))

What is (1-sin^2(x))/(dx) ?
The solution to (1-sin^2(x))/(dx) is (cos^2(x))/(dx)