What are the solutions to the equation 2x^2-14x+4=0 ?

The solutions to the equation 2x^2-14x+4=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2

Find the zeros of 2x^2-14x+4=0

The zeros of 2x^2-14x+4=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2

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2 x^{2} - 14 x + 4 = 0

x = \frac{7 + 41}{2}, x = \frac{7 - 41}{2}

Decimal Notation

x = 6.70156 \dots, x = 0.29843 \dots

Solution steps

2 x^{2} - 14 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 4 = 241

x_{1, 2} = \frac{- ( - 14 ) \pm 2 41}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 41}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 2 41}{2 \cdot 2}

x = \frac{- ( - 14 ) + 2 41}{2 \cdot 2} : \frac{7 + 41}{2}

x = \frac{- ( - 14 ) - 2 41}{2 \cdot 2} : \frac{7 - 41}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 41}{2}, x = \frac{7 - 41}{2}

(x^{6})^{\frac{1}{2}}

16 c^{2} - 9

2 x^{2} - 23 x + 30

9^{- \frac{1}{2}}

What are the solutions to the equation 2x^2-14x+4=0 ?
The solutions to the equation 2x^2-14x+4=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2
Find the zeros of 2x^2-14x+4=0
The zeros of 2x^2-14x+4=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2