What is (-i)[sin((4i+3)(iy+x)+4i+3)] ?

The solution to (-i)[sin((4i+3)(iy+x)+4i+3)] is -isin(3x-4y+i(3y+4x)+4i+3)

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simplify (-i)[sin((4i+3)(iy+x)+4i+3)]

simplify

(- i) [sin ((4 i + 3) (i y + x) + 4 i + 3)]

- i sin (3 x - 4 y + i (3 y + 4 x) + 4 i + 3)

Solution steps

(- i) (sin ((4 i + 3) (i y + x) + 4 i + 3))

Rewrite using trig identities

= (- i) sin (3 x - 4 y + i (3 y + 4 x) + 4 i + 3)

Remove parentheses:

(- a) = - a

= - i sin (3 x - 4 y + i (3 y + 4 x) + 4 i + 3)

(π + x) + cos (π - x)

7 \cdot (sin (x - \frac{2 π}{3}))

sin^{2} (x - π)

sec (2 π - x)

sin (5 π - x)

What is (-i)[sin((4i+3)(iy+x)+4i+3)] ?
The solution to (-i)[sin((4i+3)(iy+x)+4i+3)] is -isin(3x-4y+i(3y+4x)+4i+3)