What is 5cos(4x+(13pi)/8) ?

The solution to 5cos(4x+(13pi)/8) is 5((sqrt(2-\sqrt{2)})/2 cos(4x)+(sqrt(2+\sqrt{2)})/2 sin(4x))

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simplify 5cos(4x+(13pi)/8)

simplify

5 cos (4 x + \frac{13 π}{8})

5 (\frac{2 - 2}{2} cos (4 x) + \frac{2 + 2}{2} sin (4 x))

Solution steps

5 cos (4 x + \frac{13 π}{8})

Rewrite using trig identities

= 5 (\frac{2 - 2}{2} cos (4 x) + \frac{2 + 2}{2} sin (4 x))

sin (arccos (\frac{x}{( x + 1 )}))

cot (arccos (\frac{x}{14}))

cos (n \cdot (- 1) \cdot π)

4 cos (3 (- x))

sin (x - \frac{5 π}{2})

What is 5cos(4x+(13pi)/8) ?
The solution to 5cos(4x+(13pi)/8) is 5((sqrt(2-\sqrt{2)})/2 cos(4x)+(sqrt(2+\sqrt{2)})/2 sin(4x))