What is (tan(pi/2+θ)x+y)^2 ?

The solution to (tan(pi/2+θ)x+y)^2 is (-xcot(θ)+y)^2

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simplify (tan(pi/2+θ)x+y)^2

simplify

(tan (\frac{π}{2} + θ) x + y)^{2}

(- x cot (θ) + y)^{2}

Solution steps

(tan (\frac{π}{2} + θ) x + y)^{2}

Rewrite using trig identities

= ((- \frac{cos ( θ )}{sin ( θ )}) x + y)^{2}

Simplify

((- \frac{cos ( θ )}{sin ( θ )}) x + y)^{2} : (- \frac{x cos ( θ )}{sin ( θ )} + y)^{2}

= (- \frac{x cos ( θ )}{sin ( θ )} + y)^{2}

Use the basic trigonometric identity:

\frac{cos ( x )}{sin ( x )} = cot (x)

= (- x cot (θ) + y)^{2}

tan (arccos (\frac{x}{14}))

sin (sin (x + 2 π))

2 cos (x) + 7 cos (4 5^{\circ} - x)

sin (x - \frac{5 π}{3})

cos (2 x + 3 0^{\circ})

What is (tan(pi/2+θ)x+y)^2 ?
The solution to (tan(pi/2+θ)x+y)^2 is (-xcot(θ)+y)^2