What is 1/(sin(40deg)) ?

The solution to 1/(sin(40deg)) is csc(40deg)

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simplify 1/(sin(40deg))

simplify

\frac{1}{sin ( 40 d e g )}

csc (40 d e g)

Solution steps

\frac{1}{sin ( 40 d e g )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= csc (40 d e g)

\frac{ln ( x ^{2} )}{sin ( 3 x )}

a rco sin (- \frac{1}{4})

- cos (2 x) - (- cos (- 2 x))

tan (- ln (cos (x)))

4 cos^{2} (x) - 4 cos (- x) - 3