What is +sqrt((x-2)/(x^2-1))>= 0 ?

The solution to +sqrt((x-2)/(x^2-1))>= 0 is -1 = 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

+sqrt((x-2)/(x^2-1))>= 0

+ \frac{x - 2}{x ^{2} - 1} \geq 0

- 1 < x < 1 or x \geq 2

Interval Notation

(- 1, 1) \cup [2, \infty)

Solution steps

\frac{x - 2}{x ^{2} - 1} \geq 0

If n is even,

for all

u

True for all x

Find singularity points

Find non-negative values for radicals:

- 1 < x < 1 or x \geq 2

Combine the intervals

True for all x and (- 1 < x < 1 or x \geq 2)

Merge Overlapping Intervals

- 1 < x < 1 or x \geq 2

(a - b)^{3} + b^{3}

9 = - 6 + u

5 x^{2} - 10 x - 1 = 0

8 x^{2} - 24

(5 b^{2})^{3} (\frac{1}{2} b^{3})^{2}

What is +sqrt((x-2)/(x^2-1))>= 0 ?
The solution to +sqrt((x-2)/(x^2-1))>= 0 is -1<x<1\lor x>= 2