What is (vcos(wt-pi/4))^2 ?

The solution to (vcos(wt-pi/4))^2 is (v^2(cos(wt)+sin(wt))^2)/2

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simplify (vcos(wt-pi/4))^2

simplify

(v cos (wt - \frac{π}{4}))^{2}

\frac{v ^{2} ( cos ( wt ) + sin ( wt ) ) ^{2}}{2}

Solution steps

(v cos (wt - \frac{π}{4}))^{2}

Rewrite using trig identities

= (v \frac{2 cos ( wt ) + 2 sin ( wt )}{2})^{2}

Simplify

(v \frac{2 cos ( wt ) + 2 sin ( wt )}{2})^{2} : \frac{v ^{2} ( cos ( wt ) + sin ( wt ) ) ^{2}}{2}

= \frac{v ^{2} ( cos ( wt ) + sin ( wt ) ) ^{2}}{2}

cos (π + x) + cos (\cdot (- π))

cos (- n^{180})

cos (nπ) \cdot 0

15 sec (x - \frac{π}{6})

cos (\frac{π}{2} + y)

What is (vcos(wt-pi/4))^2 ?
The solution to (vcos(wt-pi/4))^2 is (v^2(cos(wt)+sin(wt))^2)/2