What is (L^2)(-(cos(npi))/(npiL)) ?

The solution to (L^2)(-(cos(npi))/(npiL)) is -((-1)^nL)/(pin)

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simplify (L^2)(-(cos(npi))/(npiL))

simplify

(L^{2}) (- \frac{cos ( nπ )}{nπ L})

- \frac{( - 1 ) ^{n} L}{πn}

Solution steps

(L^{2}) (- \frac{cos ( nπ )}{nπ L})

Use the basic trigonometric identity:

cos (nπ) = (- 1)^{n}

= L^{2} (- \frac{( - 1 ) ^{n}}{nπ L})

Simplify

= - \frac{( - 1 ) ^{n} L}{πn}

cos (p ii)

- x sin (- x)

cos (π + x) + cos (x)

- tan (x) - cot (27 0^{\circ} - x)

sin (- t) cos (- t)

What is (L^2)(-(cos(npi))/(npiL)) ?
The solution to (L^2)(-(cos(npi))/(npiL)) is -((-1)^nL)/(pin)