What is sin(pi/2-(npi)/2) ?

The solution to sin(pi/2-(npi)/2) is cos((pin)/2)

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simplify sin(pi/2-(npi)/2)

simplify

sin (\frac{π}{2} - \frac{nπ}{2})

cos (\frac{πn}{2})

Solution steps

sin (\frac{π}{2} - \frac{nπ}{2})

Rewrite using trig identities

= cos (\frac{πn}{2})

2 sin (2 x + \frac{2 π}{3}) + 1

sin (- 4 π t + 4 π)

sin (arccos (\frac{x}{y}))

sin (χ - 6 0^{\circ})

2 sin (w (1.0475) + 90)