What is 1/n (sin(n-pi)) ?

The solution to 1/n (sin(n-pi)) is -(sin(n))/n

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simplify 1/n (sin(n-pi))

simplify

\frac{1}{n} (sin (n - π))

- \frac{sin ( n )}{n}

Solution steps

\frac{1}{n} (sin (n - π))

Rewrite using trig identities

= \frac{1}{n} (- sin (n))

Simplify

\frac{1}{n} (- sin (n)) : - \frac{sin ( n )}{n}

= - \frac{sin ( n )}{n}

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