What is (dx)/(cos(2x)cos^2(x)) ?

The solution to (dx)/(cos(2x)cos^2(x)) is sec^2(x)sec(2x)dx

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simplify (dx)/(cos(2x)cos^2(x))

simplify

\frac{d x}{cos ( 2 x ) cos ^{2} ( x )}

sec^{2} (x) sec (2 x) d x

Solution steps

\frac{d x}{cos ( 2 x ) cos ^{2} ( x )}

Use the basic trigonometric identity:

\frac{1}{cos ( x )} = sec (x)

= d x sec (2 x) sec^{2} (x)

sin (\frac{3 πn}{3})

2 cos (4 5^{\circ} + θ)

- sin (0.025 x) + sin (- 0.025 x)

x + 15 cos (x + 4 π)

sin (\frac{10 π}{2} + θ)

What is (dx)/(cos(2x)cos^2(x)) ?
The solution to (dx)/(cos(2x)cos^2(x)) is sec^2(x)sec(2x)dx