What are the solutions to the equation 1/8 x^2+4x+28=0 ?

The solutions to the equation 1/8 x^2+4x+28=0 are x=4(sqrt(2)-4),x=-4(4+sqrt(2))

Find the zeros of 1/8 x^2+4x+28=0

The zeros of 1/8 x^2+4x+28=0 are x=4(sqrt(2)-4),x=-4(4+sqrt(2))

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\frac{1}{8} x^{2} + 4 x + 28 = 0

x = 4 (2 - 4), x = - 4 (4 + 2)

Decimal Notation

x = - 10.34314 \dots, x = - 21.65685 \dots

Solution steps

\frac{1}{8} x^{2} + 4 x + 28 = 0

Multiply both sides by

8

x^{2} + 32 x + 224 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 1 \cdot 224}{2 \cdot 1}

3 2^{2} - 4 \cdot 1 \cdot 224 = 82

x_{1, 2} = \frac{- 32 \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 32 + 8 2}{2 \cdot 1}, x_{2} = \frac{- 32 - 8 2}{2 \cdot 1}

x = \frac{- 32 + 8 2}{2 \cdot 1} : 4 (2 - 4)

x = \frac{- 32 - 8 2}{2 \cdot 1} : - 4 (4 + 2)

The solutions to the quadratic equation are:

x = 4 (2 - 4), x = - 4 (4 + 2)

\frac{π}{4} \cdot 4

- x^{2} + 7 x - 10 \geq 0

\frac{( 2 t + 5 ) ( 3 t - 1 )}{3} + \frac{t ^{2} + 5}{2} = \frac{7 t - 5}{6} + 1

∣ 2 x ∣ = x^{2} - 3

4 x^{3} + 12 x^{2} - x - 3

What are the solutions to the equation 1/8 x^2+4x+28=0 ?
The solutions to the equation 1/8 x^2+4x+28=0 are x=4(sqrt(2)-4),x=-4(4+sqrt(2))
Find the zeros of 1/8 x^2+4x+28=0
The zeros of 1/8 x^2+4x+28=0 are x=4(sqrt(2)-4),x=-4(4+sqrt(2))