What is sin(npi)-sin(0) ?

The solution to sin(npi)-sin(0) is 0

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simplify sin(npi)-sin(0)

simplify

sin (nπ) - sin (0)

0

Solution steps

sin (nπ) - sin (0)

Use the basic trigonometric identity:

sin (nπ) = 0

= - sin (0) + 0

Use the following trivial identity:

sin (0) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= - 0 + 0

Simplify

= 0

sin (arccot (3 x))

- sin^{2} (18 0^{\circ} + x)

cos (arctan (\frac{4}{3}) + p in)

f (x) = sec (2) tan (x)

2 tan (x + \frac{π}{2})