What is tan(pi-θ)+tan(pi+θ) ?

The solution to tan(pi-θ)+tan(pi+θ) is 0

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simplify tan(pi-θ)+tan(pi+θ)

simplify

tan (π - θ) + tan (π + θ)

0

Solution steps

tan (π - θ) + tan (π + θ)

Rewrite using trig identities

= tan (π - θ) + \frac{sin ( θ )}{cos ( θ )}

Rewrite using trig identities

= - \frac{sin ( θ )}{cos ( θ )} + \frac{sin ( θ )}{cos ( θ )}

Add similar elements:

- \frac{sin ( θ )}{cos ( θ )} + \frac{sin ( θ )}{cos ( θ )} = 0

= 0

- a cos (\frac{π}{2} - b x)

sec (18 0^{\circ} + x)

cos (5 π - x)

sin (a - 3 π)

cos (π - arccos (x))