What are the solutions to the equation (2x-5)^2=8 ?

The solutions to the equation (2x-5)^2=8 are x=(2sqrt(2)+5)/2 ,x=(-2sqrt(2)+5)/2

Find the zeros of (2x-5)^2=8

The zeros of (2x-5)^2=8 are x=(2sqrt(2)+5)/2 ,x=(-2sqrt(2)+5)/2

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(2 x - 5)^{2} = 8

x = \frac{2 2 + 5}{2}, x = \frac{- 2 2 + 5}{2}

Decimal Notation

x = 3.91421 \dots, x = 1.08578 \dots

Solution steps

(2 x - 5)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 8 : x = \frac{2 2 + 5}{2}

Solve

2 x - 5 = - 8 : x = \frac{- 2 2 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{2 2 + 5}{2}, x = \frac{- 2 2 + 5}{2}

4!

4.4 = x - 5.6

x^{3} - 4 x^{2} - x + 4 \geq 0

x^{2} = 6 x - 9

4 - 5

What are the solutions to the equation (2x-5)^2=8 ?
The solutions to the equation (2x-5)^2=8 are x=(2sqrt(2)+5)/2 ,x=(-2sqrt(2)+5)/2
Find the zeros of (2x-5)^2=8
The zeros of (2x-5)^2=8 are x=(2sqrt(2)+5)/2 ,x=(-2sqrt(2)+5)/2