What are the solutions to the equation 4x^2-4x+3=0 ?

The solutions to the equation 4x^2-4x+3=0 are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2

Find the zeros of 4x^2-4x+3=0

The zeros of 4x^2-4x+3=0 are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2

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4 x^{2} - 4 x + 3 = 0

x = \frac{1}{2} + i \frac{2}{2}, x = \frac{1}{2} - i \frac{2}{2}

Solution steps

4 x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 3 : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 4} : \frac{1}{2} + i \frac{2}{2}

x = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 4} : \frac{1}{2} - i \frac{2}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{2}{2}, x = \frac{1}{2} - i \frac{2}{2}

\frac{p ^{2}}{q} \times \frac{q ^{2}}{p}

2 x^{2} - 7 x + 2 = 0

i^{81}

2 n^{2} - n - 15

3 (x + 3)^{2} - 81 = 0

What are the solutions to the equation 4x^2-4x+3=0 ?
The solutions to the equation 4x^2-4x+3=0 are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2
Find the zeros of 4x^2-4x+3=0
The zeros of 4x^2-4x+3=0 are x= 1/2+i(sqrt(2))/2 ,x= 1/2-i(sqrt(2))/2