What is 2sin(θ)cos(θ)+1-sin^2(θ) ?

The solution to 2sin(θ)cos(θ)+1-sin^2(θ) is cos^2(θ)+sin(2θ)

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simplify 2sin(θ)cos(θ)+1-sin^2(θ)

simplify

2 sin (θ) cos (θ) + 1 - sin^{2} (θ)

cos^{2} (θ) + sin (2 θ)

Solution steps

2 sin (θ) cos (θ) + 1 - sin^{2} (θ)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 θ) + 1 - sin^{2} (θ)

Rewrite using trig identities

= cos^{2} (θ) + sin (2 θ)

sin^{3} (π + X)

sin (arcsin (\frac{1}{x}))

cos (4 x + \frac{π}{2})

4 sin (2 x + 3 π) - 3

cos (0 - ab c)

What is 2sin(θ)cos(θ)+1-sin^2(θ) ?
The solution to 2sin(θ)cos(θ)+1-sin^2(θ) is cos^2(θ)+sin(2θ)