What is cos(2x-(5pi)/6)-sin(2x) ?

The solution to cos(2x-(5pi)/6)-sin(2x) is -(sqrt(3))/2 cos(2x)-1/2 sin(2x)

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simplify cos(2x-(5pi)/6)-sin(2x)

simplify

cos (2 x - \frac{5 π}{6}) - sin (2 x)

- \frac{3}{2} cos (2 x) - \frac{1}{2} sin (2 x)

Solution steps

cos (2 x - \frac{5 π}{6}) - sin (2 x)

Rewrite using trig identities

= - \frac{3}{2} cos (2 x) + \frac{1}{2} sin (2 x) - sin (2 x)

Add similar elements:

\frac{1}{2} sin (2 x) - sin (2 x) = - \frac{1}{2} sin (2 x)

= - \frac{3}{2} cos (2 x) - \frac{1}{2} sin (2 x)

- cos (\frac{π}{2} - θ) r a d

5 sin (x + π)

[sin (- 1 cos (x^{2} - 1))]

tan (\frac{π}{3} - x)

sin (x + \frac{π}{2}) cos (x)

What is cos(2x-(5pi)/6)-sin(2x) ?
The solution to cos(2x-(5pi)/6)-sin(2x) is -(sqrt(3))/2 cos(2x)-1/2 sin(2x)