What is tan(arctan(0)+arcsin(4x)) ?

The solution to tan(arctan(0)+arcsin(4x)) is (4xsqrt(1-16x^2))/(1-16x^2)

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simplify tan(arctan(0)+arcsin(4x))

simplify

tan (arctan (0) + arcsin (4 x))

\frac{4 x 1 - 16 x ^{2}}{1 - 16 x ^{2}}

Solution steps

tan (arctan (0) + arcsin (4 x))

Rewrite using trig identities

= \frac{sin ( arcsin ( 4 x ) )}{cos ( arcsin ( 4 x ) )}

Use the following identity:

cos (arcsin (x)) = 1 - x^{2}

= \frac{sin ( arcsin ( 4 x ) )}{1 - ( 4 x ) ^{2}}

Use the following identity:

sin (arcsin (x)) = x

= \frac{4 x}{1 - ( 4 x ) ^{2}}

Simplify

= \frac{4 x 1 - 16 x ^{2}}{1 - 16 x ^{2}}

tan (θ - 9 0^{\circ})

r^{2} (1 - sin^{2} (2 t))

- csc^{2} (- csc^{2} (x))

cot (arccos (\frac{1}{v}))

ln (- \frac{1}{cos ( x )})

What is tan(arctan(0)+arcsin(4x)) ?
The solution to tan(arctan(0)+arcsin(4x)) is (4xsqrt(1-16x^2))/(1-16x^2)