What is sin(2npi)-sin(npi) ?

The solution to sin(2npi)-sin(npi) is sin(2pin)

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simplify sin(2npi)-sin(npi)

simplify

sin (2 nπ) - sin (nπ)

sin (2 πn)

Solution steps

sin (2 nπ) - sin (nπ)

Use the basic trigonometric identity:

sin (nπ) = 0

= sin (2 nπ) - 0

sin (2 nπ) - 0 = sin (2 nπ)

= sin (2 πn)

csc (arctan (\frac{x}{5}))

tan (5 π + a)

sin (arctan (x) + arccos (0))

- cos (x - π)

2 cos (\frac{π}{4} - x)