What is 1/(sin^2(x))dx ?

The solution to 1/(sin^2(x))dx is csc^2(x)dx

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simplify 1/(sin^2(x))dx

simplify

\frac{1}{sin ^{2} ( x )} d x

csc^{2} (x) d x

Solution steps

\frac{1}{sin ^{2} ( x )} d x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot d x}{sin ^{2} ( x )}

Multiply:

1 \cdot d x = d x

= \frac{d x}{sin ^{2} ( x )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= d x csc^{2} (x)

- tan (arctan (x))

a r cos (\frac{- 2}{20})

cos (9 π - a)

tan (\frac{3 π}{2} + α)

cos (arcsin (\frac{( x - h )}{r}))