What is sin((npi)/2)-sin(npi) ?

The solution to sin((npi)/2)-sin(npi) is sin((pin)/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify sin((npi)/2)-sin(npi)

simplify

sin (\frac{nπ}{2}) - sin (nπ)

sin (\frac{πn}{2})

Solution steps

sin (\frac{nπ}{2}) - sin (nπ)

Use the basic trigonometric identity:

sin (nπ) = 0

= sin (\frac{nπ}{2}) - 0

sin (\frac{nπ}{2}) - 0 = sin (\frac{nπ}{2})

= sin (\frac{πn}{2})

4 cos (100 π t + π)

\frac{1}{csc ( θ ) sin ( - θ )}

\frac{y ^{2}}{sin ( x )} d y

- 3 sin (2 x - \frac{π}{3})

(1 - sin^{2} (x))^{\frac{3}{2}}

What is sin((npi)/2)-sin(npi) ?
The solution to sin((npi)/2)-sin(npi) is sin((pin)/2)