What is cos(b)x-cos(pi/2-bx) ?

The solution to cos(b)x-cos(pi/2-bx) is xcos(b)-sin(bx)

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simplify cos(b)x-cos(pi/2-bx)

simplify

cos (b) x - cos (\frac{π}{2} - b x)

x cos (b) - sin (b x)

Solution steps

cos (b) x - cos (\frac{π}{2} - b x)

Rewrite using trig identities

= cos (b) x - sin (b x)

tan (e^{6 (x - y)} - 1 - e^{6 (x - y)})

sin (arccos (\frac{1}{x}))

- 3 cos (4 x + \frac{π}{3})

- tan (arctan (x) + \frac{π}{4})

csc (30 π + x)

What is cos(b)x-cos(pi/2-bx) ?
The solution to cos(b)x-cos(pi/2-bx) is xcos(b)-sin(bx)