What are the solutions to the equation x^2+5x+2=-4 ?

The solutions to the equation x^2+5x+2=-4 are x=-2,x=-3

Find the zeros of x^2+5x+2=-4

The zeros of x^2+5x+2=-4 are x=-2,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 5 x + 2 = - 4

x = - 2, x = - 3

Solution steps

x^{2} + 5 x + 2 = - 4

Move

4

to the left side

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

3 x^{2} + (k + 1) x - 2 = 0

x, x^{2} - k x + 64 = 0

(3 - x)^{2} + x^{2} = 2 (5 - x)

- 6 x^{2} - 8 (- 8 + 4) = 8

25 x^{2} + 18 x - 2 = 0

What are the solutions to the equation x^2+5x+2=-4 ?
The solutions to the equation x^2+5x+2=-4 are x=-2,x=-3
Find the zeros of x^2+5x+2=-4
The zeros of x^2+5x+2=-4 are x=-2,x=-3