What is (4x^{-2}y^4)/(8x^3(y^{-2))^3} ?

The solution to (4x^{-2}y^4)/(8x^3(y^{-2))^3} is (y^{10})/(2x^5)

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simplify (4x^{-2}y^4)/(8x^3(y^{-2))^3}

simplify

\frac{4 x ^{- 2} y ^{4}}{8 x ^{3} ( y ^{- 2} ) ^{3}}

\frac{y ^{10}}{2 x ^{5}}

Solution steps

\frac{4 x ^{- 2} y ^{4}}{8 x ^{3} ( y ^{- 2} ) ^{3}}

Simplify

(y^{- 2})^{3} : \frac{1}{y ^{6}}

= \frac{4 x ^{- 2} y ^{4}}{8 x ^{3} \frac{1}{y ^{6}}}

Factor the number:

8 = 4 \cdot 2

= \frac{4 x ^{- 2} y ^{4}}{4 \cdot 2 x ^{3} \frac{1}{y ^{6}}}

Cancel the common factor:

4

= \frac{x ^{- 2} y ^{4}}{2 x ^{3} \frac{1}{y ^{6}}}

Simplify

\frac{x ^{- 2}}{x ^{3}} : \frac{1}{x ^{5}}

= \frac{y ^{4}}{2 x ^{5} \frac{1}{y ^{6}}}

Simplify

\frac{y ^{4}}{2 x ^{5} \frac{1}{y ^{6}}} : \frac{y ^{10}}{2 x ^{5}}

= \frac{y ^{10}}{2 x ^{5}}

7 x^{2} + 9 x y + 2 y^{2}

∣ x + 1 ∣ = ∣ 3 - x ∣

x^{2} + x - 6

∣ x + 4 ∣ = 3

What is (4x^{-2}y^4)/(8x^3(y^{-2))^3} ?
The solution to (4x^{-2}y^4)/(8x^3(y^{-2))^3} is (y^{10})/(2x^5)