What are the solutions to the equation 576x^2-144x+25=0 ?

The solutions to the equation 576x^2-144x+25=0 are x= 1/8+i 1/6 ,x= 1/8-i 1/6

Find the zeros of 576x^2-144x+25=0

The zeros of 576x^2-144x+25=0 are x= 1/8+i 1/6 ,x= 1/8-i 1/6

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576 x^{2} - 144 x + 25 = 0

x = \frac{1}{8} + i \frac{1}{6}, x = \frac{1}{8} - i \frac{1}{6}

Solution steps

576 x^{2} - 144 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 144 ) \pm ( - 144 ) ^{2} - 4 \cdot 576 \cdot 25}{2 \cdot 576}

Simplify

(- 144)^{2} - 4 \cdot 576 \cdot 25 : 192 i

x_{1, 2} = \frac{- ( - 144 ) \pm 192 i}{2 \cdot 576}

Separate the solutions

x_{1} = \frac{- ( - 144 ) + 192 i}{2 \cdot 576}, x_{2} = \frac{- ( - 144 ) - 192 i}{2 \cdot 576}

x = \frac{- ( - 144 ) + 192 i}{2 \cdot 576} : \frac{1}{8} + i \frac{1}{6}

x = \frac{- ( - 144 ) - 192 i}{2 \cdot 576} : \frac{1}{8} - i \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{1}{6}, x = \frac{1}{8} - i \frac{1}{6}

50 x^{2} - 50 x + 13 = 0

72 = (8 x + 3) (8 x - 3)

36 x^{2} - \frac{49}{64} = 0

x^{2} + 8 x + 96 = 0

y, x^{2} + y^{2} = c e^{2 x}

What are the solutions to the equation 576x^2-144x+25=0 ?
The solutions to the equation 576x^2-144x+25=0 are x= 1/8+i 1/6 ,x= 1/8-i 1/6
Find the zeros of 576x^2-144x+25=0
The zeros of 576x^2-144x+25=0 are x= 1/8+i 1/6 ,x= 1/8-i 1/6