What are the solutions to the equation 2(x-2)^2=12 ?

The solutions to the equation 2(x-2)^2=12 are x=sqrt(6)+2,x=-sqrt(6)+2

Find the zeros of 2(x-2)^2=12

The zeros of 2(x-2)^2=12 are x=sqrt(6)+2,x=-sqrt(6)+2

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2 (x - 2)^{2} = 12

x = 6 + 2, x = - 6 + 2

Solution steps

2 (x - 2)^{2} = 12

Divide both sides by

2

(x - 2)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 6 : x = 6 + 2

Solve

x - 2 = - 6 : x = - 6 + 2

The solutions to the quadratic equation are:

x = 6 + 2, x = - 6 + 2

4 x^{2} - 3 = 9

(x + 4)^{3} - (x - 1)^{3} = 343

x^{2} + 4 b = 0, b < 0

(2 x - 1) (2 + x) = (x - 2) (x + 1)

x^{2} + 5 x + 2 = 4

What are the solutions to the equation 2(x-2)^2=12 ?
The solutions to the equation 2(x-2)^2=12 are x=sqrt(6)+2,x=-sqrt(6)+2
Find the zeros of 2(x-2)^2=12
The zeros of 2(x-2)^2=12 are x=sqrt(6)+2,x=-sqrt(6)+2