What are the solutions to the equation 3(x-3)^2=27 ?

The solutions to the equation 3(x-3)^2=27 are x=6,x=0

Find the zeros of 3(x-3)^2=27

The zeros of 3(x-3)^2=27 are x=6,x=0

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3 (x - 3)^{2} = 27

x = 6, x = 0

Solution steps

3 (x - 3)^{2} = 27

Divide both sides by

3

(x - 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 9 : x = 6

Solve

x - 3 = - 9 : x = 0

The solutions to the quadratic equation are:

x = 6, x = 0

(2 x - 1)^{2} - 5 (2 x - 1) - 6 = 0

(2 x + 1)^{2} + (2 x + 3)^{2} = 290

5 x^{2} - 3 x - 36 = 0

9 x^{2} + 36 x + 36 = 0

7 x^{2} - 8 x - 11 = 0

What are the solutions to the equation 3(x-3)^2=27 ?
The solutions to the equation 3(x-3)^2=27 are x=6,x=0
Find the zeros of 3(x-3)^2=27
The zeros of 3(x-3)^2=27 are x=6,x=0