What are the solutions to the equation (x+9)(x-2)=60 ?

The solutions to the equation (x+9)(x-2)=60 are x=6,x=-13

Find the zeros of (x+9)(x-2)=60

The zeros of (x+9)(x-2)=60 are x=6,x=-13

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(x + 9) (x - 2) = 60

x = 6, x = - 13

Solution steps

(x + 9) (x - 2) = 60

Expand

(x + 9) (x - 2) : x^{2} + 7 x - 18

x^{2} + 7 x - 18 = 60

Move

60

to the left side

x^{2} + 7 x - 78 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 78 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 78) = 19

x_{1, 2} = \frac{- 7 \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 19}{2 \cdot 1}, x_{2} = \frac{- 7 - 19}{2 \cdot 1}

x = \frac{- 7 + 19}{2 \cdot 1} : 6

x = \frac{- 7 - 19}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 6, x = - 13

x, ln (y) = A x^{2} + B

2 x^{2} - 4 x = 12 x - 32

(x + 1)^{2} = 2 (x - 3)

x + 3 = (2 - x)^{2}

x^{2} - 4 x + 3 x - 2 = 28

What are the solutions to the equation (x+9)(x-2)=60 ?
The solutions to the equation (x+9)(x-2)=60 are x=6,x=-13
Find the zeros of (x+9)(x-2)=60
The zeros of (x+9)(x-2)=60 are x=6,x=-13