What are the solutions to the equation 2(x-5)^2=17 ?

The solutions to the equation 2(x-5)^2=17 are x=sqrt(17/2)+5,x=-sqrt(17/2)+5

Find the zeros of 2(x-5)^2=17

The zeros of 2(x-5)^2=17 are x=sqrt(17/2)+5,x=-sqrt(17/2)+5

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2 (x - 5)^{2} = 17

x = \frac{17}{2} + 5, x = - \frac{17}{2} + 5

Decimal Notation

x = 7.91547 \dots, x = 2.08452 \dots

Solution steps

2 (x - 5)^{2} = 17

Divide both sides by

2

(x - 5)^{2} = \frac{17}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = \frac{17}{2} : x = \frac{17}{2} + 5

Solve

x - 5 = - \frac{17}{2} : x = - \frac{17}{2} + 5

The solutions to the quadratic equation are:

x = \frac{17}{2} + 5, x = - \frac{17}{2} + 5

2 x^{2} - 12 x = 3

3 (x + 6) = x^{2}

x^{2} - 2 b x^{2} + b^{2} - a = 0

x + 5 = \frac{( x - 7 ) ^{2}}{2}

0.1 n^{2} + 100 n + 8 = 1000

What are the solutions to the equation 2(x-5)^2=17 ?
The solutions to the equation 2(x-5)^2=17 are x=sqrt(17/2)+5,x=-sqrt(17/2)+5
Find the zeros of 2(x-5)^2=17
The zeros of 2(x-5)^2=17 are x=sqrt(17/2)+5,x=-sqrt(17/2)+5