What are the solutions to the equation 16x^2-24x+7=0 ?

The solutions to the equation 16x^2-24x+7=0 are x=(3+sqrt(2))/4 ,x=(3-sqrt(2))/4

Find the zeros of 16x^2-24x+7=0

The zeros of 16x^2-24x+7=0 are x=(3+sqrt(2))/4 ,x=(3-sqrt(2))/4

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16 x^{2} - 24 x + 7 = 0

x = \frac{3 + 2}{4}, x = \frac{3 - 2}{4}

Decimal Notation

x = 1.10355 \dots, x = 0.39644 \dots

Solution steps

16 x^{2} - 24 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 7}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 7 = 82

x_{1, 2} = \frac{- ( - 24 ) \pm 8 2}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8 2}{2 \cdot 16}, x_{2} = \frac{- ( - 24 ) - 8 2}{2 \cdot 16}

x = \frac{- ( - 24 ) + 8 2}{2 \cdot 16} : \frac{3 + 2}{4}

x = \frac{- ( - 24 ) - 8 2}{2 \cdot 16} : \frac{3 - 2}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 2}{4}, x = \frac{3 - 2}{4}

(w - 8) (w + 5) = 14

6 x^{2} - 8 x + 1

(r - 7)^{2} = 81

2 x^{2} - 7 x + 9 = (x - 3) (x + 1) + 3 x

2 x (x + 3) + 1 = 0

What are the solutions to the equation 16x^2-24x+7=0 ?
The solutions to the equation 16x^2-24x+7=0 are x=(3+sqrt(2))/4 ,x=(3-sqrt(2))/4
Find the zeros of 16x^2-24x+7=0
The zeros of 16x^2-24x+7=0 are x=(3+sqrt(2))/4 ,x=(3-sqrt(2))/4