What are the solutions to the equation x^2=a,a<0 ?

The solutions to the equation x^2=a,a<0 are x=sqrt(a),x=-sqrt(a)

Find the zeros of x^2=a,a<0

The zeros of x^2=a,a<0 are x=sqrt(a),x=-sqrt(a)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

The solutions to the equation x^2=a,a<0 are x=sqrt(a),x=-sqrt(a)

The zeros of x^2=a,a<0 are x=sqrt(a),x=-sqrt(a)

x^{2} = a, a < 0

x = a, x = - a

Solution steps

x^{2} = a, a < 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = a, x = - a

x^{2} = 8 x + 12

\frac{1}{2} x^{2} - x - 2 = 0

(2 x - 1)^{2} - x (x - 3) = 5

(2 x - 7)^{2} - 3 = 0

4 (1 + 4 x) = x (x - 7)

What are the solutions to the equation x^2=a,a<0 ?
The solutions to the equation x^2=a,a<0 are x=sqrt(a),x=-sqrt(a)
Find the zeros of x^2=a,a<0
The zeros of x^2=a,a<0 are x=sqrt(a),x=-sqrt(a)