What are the solutions to the equation x^2-4x-20=-5x ?

The solutions to the equation x^2-4x-20=-5x are x=4,x=-5

Find the zeros of x^2-4x-20=-5x

The zeros of x^2-4x-20=-5x are x=4,x=-5

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x^{2} - 4 x - 20 = - 5 x

x = 4, x = - 5

Solution steps

x^{2} - 4 x - 20 = - 5 x

Move

5 x

to the left side

x^{2} + x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 1}, x_{2} = \frac{- 1 - 9}{2 \cdot 1}

x = \frac{- 1 + 9}{2 \cdot 1} : 4

x = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

(2 - x)^{2} - (2 x - 3)^{2} = 50

(5 - x)^{2} - (3 x - 1)^{2} = 0

(y + 2)^{2} = - 9

(x + 2) (2 x - 3) = 3 x - 7

3 x - (2 - x) - 2 = (x + 1) (2 - 3 x)

What are the solutions to the equation x^2-4x-20=-5x ?
The solutions to the equation x^2-4x-20=-5x are x=4,x=-5
Find the zeros of x^2-4x-20=-5x
The zeros of x^2-4x-20=-5x are x=4,x=-5