What are the solutions to the equation x^2-7x-10=-2x-4 ?

The solutions to the equation x^2-7x-10=-2x-4 are x=6,x=-1

Find the zeros of x^2-7x-10=-2x-4

The zeros of x^2-7x-10=-2x-4 are x=6,x=-1

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x^{2} - 7 x - 10 = - 2 x - 4

x = 6, x = - 1

Solution steps

x^{2} - 7 x - 10 = - 2 x - 4

Move

4

to the left side

x^{2} - 7 x - 6 = - 2 x

Move

2 x

to the left side

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

x, 4 x^{2} - 4 y^{2} = 0

3 r^{2} + 3 r - 4 = 0

- 5 (2 x - 3)^{2} = - 125

x, x^{2} - 8 k x - 9 = 0

x, 5 x^{2} + x y^{2} = C

What are the solutions to the equation x^2-7x-10=-2x-4 ?
The solutions to the equation x^2-7x-10=-2x-4 are x=6,x=-1
Find the zeros of x^2-7x-10=-2x-4
The zeros of x^2-7x-10=-2x-4 are x=6,x=-1