What are the solutions to the equation (5-x)(2x+3)=0 ?

The solutions to the equation (5-x)(2x+3)=0 are x=5,x=-3/2

Find the zeros of (5-x)(2x+3)=0

The zeros of (5-x)(2x+3)=0 are x=5,x=-3/2

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(5 - x) (2 x + 3) = 0

x = 5, x = - \frac{3}{2}

Solution steps

(5 - x) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 - x = 0 or 2 x + 3 = 0

Solve

5 - x = 0 : x = 5

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{2}

3 x^{2} - 132 = 0

(3 - x) (1 + 2 x) = - 9

(x + 3)^{2} + (x + 2)^{2} = 9

4 = x^{2} + 10 x

2 x - 5 (x + 3) = x (x - 4)

What are the solutions to the equation (5-x)(2x+3)=0 ?
The solutions to the equation (5-x)(2x+3)=0 are x=5,x=-3/2
Find the zeros of (5-x)(2x+3)=0
The zeros of (5-x)(2x+3)=0 are x=5,x=-3/2